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4 years ago

Which is more, 6 kilometers or 5,998 meters?

1 answer:

5 0

kilometers is larger. This is because when you convert 6 Kilometers into meters you get 6000 which is surely larger then 5,998 I hope this answers you question.

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Find x. Round to the nearest tenth.

In-s [12.5K]

Answer:

x = 4.9

Step-by-step explanation:

We can use the intersecting chords formula:

(segment piece) x (segment piece) = (segment piece) x (segment piece)

7*7 = 10x

49 = 10x

Divide each side by 10

49/10=10x/10

4.9 = x

8 0

4 years ago

X - 3 = 8 4 Plsss help

Law Incorporation [45]

Answer:

X=81

Step-by-step explanation:

X-3=84

X=84-3=>81

3 0

3 years ago

Randy coffee shop sells a refill mug for $8.95. Each refill costs $1.50. Last month Sean spent $26.95 on a mug and refills. How

Ratling [72]

Answer:

The answer is 12

Step-by-step explanation:

Step 1: $26.95 - $8.95 (which equals $18.00)

Step 2: 18 divided by 1.50 (which equals 12)

5 0

4 years ago

12x -20=n (3x-5) I need help I don’t get it please help me.

Salsk061 [2.6K]

Answer:

The value of n = 4 and

The value of x = $\frac{5}{3}$

Step-by-step explanation:

Method I:

As given, 12x -20=n (3x-5) .........(1)

Firstly , take 12x - 20

As 12x - 20 can be written as 4(3x - 5)

∴ equation (1) becomes

4(3x - 5) = n (3x-5)

Divide the equation by (3x-5) , we get

4 = n

Method II:

As given, 12x -20=n (3x-5)

⇒12x - 20 = 3nx - 5n

⇒12x - 3nx = 20 - 5n

⇒3x(4 - n) = 5( 4 - n)

Divide the equation by (4-n) , we get

3x = 5

⇒ x = $\frac{5}{3}$

∴ we get

n = 4 and x = $\frac{5}{3}$

Now, check that value of n and x satisfies the equation or not

12( $\frac{5}{3}$ ) - 20 = 4( 3( $\frac{5}{3}$ ) - 5)

⇒4(5) - 20 = 4(5 - 5)

⇒20 - 20 = 4(0)

⇒ 0 = 0

Hence , we get

The values of x and n satisfies the equation

so, we get

n = 4 and x = $\frac{5}{3}$

5 0

3 years ago

It is estimated that t-weeks into a semester, the average amount of sleep a college math student gets per day S(t) decreases at

goldenfox [79]

Answer:

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

Step-by-step explanation:

Before to getting started ,we have to consider the function which represents sleep decline rate S'(t) = $-3te^{t^{2} } \\$

Since this function is interpreted in this case as a rate of change, we can deduce this funcion is the first derivative of the function of average amount of sleep (S(t)).

In order to find S(t), we will integrate S'(t)

$\int\limits^ {} -3t3e^{t^{2} } \, dx \\$

This case corresponds to intergration by substitution

Substituting u= $x^{2} \\$

Computting the differential of u

$\frac{du}{dt} =2tdt\\$

Now, let's go back to our integral and write it in terms of u, using both definition of u and its defferential.

$\int\limits^{}-3te^{u} \, \frac{1}{2t}du \\\\\int\limits^{}\frac{-3}{2} e^{u}du\\$

The integral of a exponential function is itself. So the result is:

$\frac{-3}{2} e^{u} +c$

Now substitute u back in:

$\frac{-3}{2} e^{t^{2} } +c$

This answer correspond to function of average amount of sleep.

We know that when the semester begins (t=0) , math students sleep an average of 8.1 hours per day so we will use this info in order to find the value of c.

$s(0)=\frac{-3}{2} e^{0^{2} } +c=8.1\\\\\frac{-3}{2} +c=8.1$

Solve this equation

c=8.1+ $\frac{3}{2}$

c=9.6

Replacing the value of c on S(t)

S(t)= $\frac{-3}{2} e^{t^{2} } +9.6$

Now, let's to find the average of amount of sleep when 15 weeks has elapsed since the start date of the semester.

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

4 0

3 years ago