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liraira [26]
3 years ago
5

For the functions f(x)=4x−3 and g(x)=3x2+4x, find (f∘g)(x) and (g∘f)(x).

Mathematics
1 answer:
barxatty [35]3 years ago
7 0

Answer:

(16x + 21) and (16x - 6)

Step-by-step explanation:

f(g(x)) = f(6 + 4x)

Applying the f(x) function on (6 + 4x) gives

4(6 + 4x) - 3

Which equals 16x + 24 - 3

= 16x + 21

g(f(x)) = g(4x - 3)

Applying the g(x) function on (4x - 3) gives

6 + 4(4x - 3)

Which equals 6 + 16x - 12

= 16x - 6

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(0, -5), (1, 0), (2, 5), (3, 10)<br> in ordered pairs
harkovskaia [24]

(2,5) (3,10) (1,0) (0, -5)

4 0
3 years ago
a store sells new DVDs for $12 each. used DVDs sell for $7 each. Joseph is buying two new DVDs and X used DVDs. write an equatio
vagabundo [1.1K]
Given that new DVDs are selling for $12 and used for $7, then Joseph is buying:
12·2 + 7<em>x </em>= 

7 0
3 years ago
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The gold bar has a trapezium cross-sectional area.
mario62 [17]

Answer:

Mass of gold bar=13.896

4 0
3 years ago
A − 7 = 3 (b+2) pls answer soon
Alexeev081 [22]
I believe the answer is....

For solving for a

a-7= 3(b+2) ———> distribute 3(b+2)
a-7= 3b+6 ———-> add 7 on both sides

a-7= 3b+6
a+7= 3b +7 ———-> the 7’s cancel out so you’re left with....

a = 3b + 13 (That’s your answer)

Hope that helped :3
8 0
3 years ago
What is an equation of the line that passes through the point (-6, -7) and is
Alexandra [31]

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b  form

        5y = -6x + 30

          y = \frac{-6}{5}x+\frac{30}{5}

          y=\frac{-6}{5}x + 6

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

      m₂ = -1÷m₁ = -1 * \frac{5}{-6}  

m_{2}=\frac{5}{6}     & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2

8 0
2 years ago
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