Answer:
The distance between (-3, 2) and (0,3) is √10.
Step-by-step explanation:
As we go from (-3,2) to (0,3), x increases by 3 and y increases by 1.
Think of a triangle with base 3 and height 1. Use the Pythagorean Theorem to find the length of the hypotenuse, which represents the distance between the points (-3, 2) and (0, 3):
distance = √(3² + 1²) = √10
The distance between (-3, 2) and (0,3) is √10.
Answer:
D
Step-by-step explanation:
100 - 35 = 55 dollars remaining
55/20 = 3.25 hours until no money
Answer:
4 or -625x^4 (Just in case I misunderstood)
Step-by-step explanation:
The degree is always the power of something. Since -5x has a power of 4, its degree is 4.
Just in case I misunderstood the question, I will solve it another way that I think you meant. (-5x)^4 is -5^4 times x^4.
-625 times x^4 is -625x^4.
Answer:
1999
Step-by-step explanation:
y = 0.2313(y - 1992)^2 + 2.600(y - 1992) + 35.17
verify with known data point
y = 0.2313(2004 - 1992)^2 + 2.600(2004 - 1992) + 35.17
y = 0.2313(12)^2 + 2.600(12) + 35.17
y = 27.9873 + 28.6 + 35.17
y = 99.6772 which verifies our equation
65 = 0.2313x² + 2.6x + 35.17
0 = 0.2313x² + 2.6x - 29.83
quadratic formula
x = (-2.6 ±√(2.6² - 4(0.2313)(-29.83))) / (2(0.2313))
x = (-2.6 + 5.86) / 0.4626 = 7.05 years
7.05 = y - 1992
y = 1999.05
9514 1404 393
Answer:
-3 ≤ x ≤ 19/3
Step-by-step explanation:
This inequality can be resolved to a compound inequality:
-7 ≤ (3x -5)/2 ≤ 7
Multiply all parts by 2.
-14 ≤ 3x -5 ≤ 14
Add 5 to all parts.
-9 ≤ 3x ≤ 19
Divide all parts by 3.
-3 ≤ x ≤ 19/3
_____
<em>Additional comment</em>
If you subtract 7 from both sides of the given inequality, it becomes ...
|(3x -5)/2| -7 ≤ 0
Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.
__
For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...
|f(x)| < (some number) . . . . or ≤
If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:
|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0
Any solutions to these inequalities must respect their domains.