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Zielflug [23.3K]
3 years ago
5

Write a decimal that is 1/10 of .9

Mathematics
1 answer:
amm18123 years ago
8 0
1/10 of .9 is the same as dividing .9 by 10. .90 / 10 = .09 .09 is the answer
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URGENT will give brilliant mark For the reaction 2Na + Cl2 ------ 2NaCl, how many grams of sodium chloride can be produced from
SVETLANKA909090 [29]

Answer:

825 g

Step-by-step explanation:

Here's my work:

500g Cl2 l   1mol Cl2  l  2 mol NaCl   l  58.5 g NaCl

                l   71 g Cl2    l  1 mol Cl2      l    1 mol NaCl  

= 823.94  - the rounding can be a little off

The first thing you have to do is convert the 500 g of Cl2 into moles.  So you get the mass of Cl which is 35.5, but Cl is diatomic by itself so you multiply 35.5 x 2 and get 71.   now on the third column you are comparing the mol ratios of the equation.  The equation is 2Na + Cl2 ---> 2NaCl, so you see that there is no coefficient in front of Cl2 so that means there is 1 mol, and then you see that in the product there is a  coefficient of 2 in front of NaCl so that means there is 2 moles.  Then finally you have to convert the moles backs into grams where you just add the masses of Na and Cl .  You multiply across the top  and then divide that number by the bottom row.

6 0
3 years ago
Solve for x. Round your answer to the nearest tenth if necessary.
eduard

Answer: 15.9

Step-by-step explanation:

7 0
2 years ago
Please help me out I need it done ASAP
irinina [24]
Your answer will be letter c
7 0
3 years ago
How much times does it take for the first black/clear part to fall through the photo gate timer, starting from the rest? Plastic
Alik [6]
I can figure out this is a frefall motion.

Starting from rest => Vo = 0

Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)

d = width of a black/clear stripe pair = 5cm = 0.05m

g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)

t =√(2*0.05m/10m/s^2) =  0.1 s

Answer: approximately 0.1 s
5 0
3 years ago
A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res
Alexus [3.1K]

Answer:

Step-by-step explanation:

Hello!

So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:

X: "Lifetime of one shoe pair of the new model"

Applying CLT:

X[bar]≈N(μ;σ²/n)

Known values:

n= 30 shoe pairs

x[bar]: 17 months

S= 5.5 months

Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:

H₀:μ=15

H₁:μ≠15

The significance level for the test is given: α: 0.05

Your critical region will be two-tailed:

Z_{\alpha /2} = Z_{0.025}= -1.96

Z_{1-\alpha /2} = Z_{0.975}= 1.96

So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96

Now you calculate your observed Z-value

Z=<u>x[bar]-μ</u> ⇒ Z=<u>    17-15     </u> = 1.99

     σ/√n              5.5/√30

Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.

I hope you have a SUPER day!

5 0
3 years ago
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