Answer:

![g(x)=\sqrt[3]{x}-5](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5)
Step-by-step explanation:
Consider the given function is
![f(x)=\sqrt[3]{-2x+4}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-2x%2B4%7D-5)
It is given that
and neither g(x) nor h(x) is solely x.
![f(x)=\sqrt[3]{(-2x+4)}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%28-2x%2B4%29%7D-5)
Let
, then we get
![f(x)=g(h(x))=\sqrt[3]{h(x)}-5](https://tex.z-dn.net/?f=f%28x%29%3Dg%28h%28x%29%29%3D%5Csqrt%5B3%5D%7Bh%28x%29%7D-5)
Substitute h(x)=x in the above function.
![g(x)=\sqrt[3]{x}-5](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5)
Therefore, the required functions are
and
.
Check the solutions.
![[\because h(x)=-2x+4]](https://tex.z-dn.net/?f=%5B%5Cbecause%20h%28x%29%3D-2x%2B4%5D)
![[\because g(x)=\sqrt[3]{x}-5]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5%5D)

Therefore, our solution is correct.
Answer:
460 mi²
Step-by-step explanation:
The surface area consists of 3 rectangles of the sides, and the two base triangles.
The front rectangle has dimensions of 10x11, so it's area is 110 in²
The left side rectangle has dimensions of 10x11, so it's area is 110 in²
The right side rectangle has dimensions of 12x11, so it's area is 132 in²
The top and bottom triangles have a base of 12 and a height of 8, so their area is
A = (1/2)(12)(8) = 108/2, but there are 2 of them, so their combined area is (108/2)(2) = 108 in²
The total surface area is 110 + 110 + 132 + 108 = 460 mi²
1.50 5/9(122-32)=5/9(90)= 50
I am assuming you are trying to find the sum.
First, plug in n for 1, then n for 80 to get the following numbers:
5/6 and 163/6
As you go up the sequence, as n is increased by 1, then the next number is increased by 1/3
Use the arithmetic sequence formula to solve for the sum.
n * (a1 + a2)/2 where a1 is 1st number and a2 is last number.
80 * (5/6 + 163/6)/2
Simplify the expression to get 1120.
Answer:
Cube 1 = 30 cubic
Cube 2 = 48 cubic
Cube 3 = 72 cubic
Step-by-step explanation:
Cube 1 = 5x2x3
Cube 2 = 6x2x4
Cube 3 = 8x3x3