Answer:
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
Explanation:
Given:
Radius of sphere (r) = 12 cm = 0.12 m
Distance from the electric field R = 24 cm = 0.24 m
Magnitude (E) = 640 N/C
Find:
Charge density on the sphere
Computation:
Charge on the sphere (q) = (1/K)ER² (K = 9 × 10⁹)
Charge on the sphere (q) = [1/(9 × 10⁹)](640)(0.24)²
Charge on the sphere (q) = 4 × 10⁻⁹ C
Charge density on the sphere = q / [4πr²]
Charge density on the sphere = [4 × 10⁻⁹] / [4(3.14)(0.12)²]
Charge density on the sphere = [4 × 10⁻⁹] / [0.18]
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
The only 'difference' is that they are different categories.
It's like asking "What's the difference between Susie and girl ?"
Or "What's the difference between Cadillac and car ?"
Displacement <em>IS</em> a vector quantity.
It is right have a good day
explanation step by step
Explanation:
It is given that,
Semi major axis of the Jupiter, 
Mass of the sun, 
(a) Let T is the period of Jupiter's orbit. It is given by :
(b) We know that,
or
T = 11.859 earth years
Hence, this is the required solution.
