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Marina86 [1]
3 years ago
15

Maria listed four important points about einstein’s special theory of relativity. 1) applies to any object moving more slowly th

an the speed of light 2) applies to objects moving in a straight path 3) describes the relationship between time and space 4) applies to uniformly moving objects which best describes how maria can correct her error? change the first point to "applies to objects moving almost at the speed of light." for point 2, include objects moving in a curved path. for point 3, replace the word "space" with the word "motion." change the fourth point to "applies to accelerating objects."
Physics
1 answer:
Arturiano [62]3 years ago
3 0

How Maria can correct her error is by changing the fourth point to "applies to accelerating objects.". Option D. This is further explained below.

<h3>What is einstein’s special theory of relativity?</h3>

Generally, Einstein’s special relativity is simply defined as how speed affects matter, time, and space.

In conclusion, The theory contains a method for defining the link between energy and matter using the speed of light.

Read more about Motion

brainly.com/question/605631

#SPJ4

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Answer:

A) hydrostatic force on top of cube = 882.9N

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Explanation:

Detailed explanation and calculation is shown in the image below

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Answer: B. CO

Explanation:

Diatomic molecules are those that are formed by two atoms of the same chemical element (homonuclear diatomic molecule) or different chemical element (heteronuclear diatomic molecule).  

In this sense, oxygen is a homonuclear diatomic molecule because it is formed by two atoms of the same element (O_{2}) and Carbon monoxide (CO) is heteronuclear diatomic molecule.

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3 years ago
Define the reflection with diagram​
LekaFEV [45]

Answer:

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Explanation:

6 0
3 years ago
I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a
drek231 [11]

Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}

<u>P₂ = 1.22 kPa</u>

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3 years ago
Yes this nees helppppppppppppppp
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Answer:

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4 years ago
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