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leva [86]
3 years ago
11

F(x) - 3x -9; g(x) = x -4 what is the value of (g o f)(x)

Mathematics
1 answer:
Ratling [72]3 years ago
6 0
-3x-13
since there is no x value the equation can not be solved any further.
:)))))


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Calculate the following limit:
aleksklad [387]
\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\
=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1


8 0
3 years ago
Can someone help me ASAP!!
Ede4ka [16]

Answer:

UR in trouble

Step-by-step explanation:

Look, the First order is the biggest force in the galaxy.

Now, it is gonna  send a star destroyer to ur house and blow it up.

5 0
2 years ago
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ELEN [110]

i will bite - this is not a complete ans but an approximation:

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there are 90*89*98 ways to pick 2 nos between 10 and 100 and a third no. between 1 and 100.

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Step-by-step explanation:

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In a school there are 500 students and 35 teachers. What is the ratio of students to teachers?
valkas [14]
The ratio is 500:35, or 14.28
8 0
3 years ago
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