if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation
now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
Answer:
.
Step-by-step explanation:
Answer:
You can draw three rectangles:
1- 28 * 1.
2- 14*2
3- 7*4
Step-by-step explanation:
We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.
28 = 1*2*2*7
We can organize them as follows:
R1: 28 = 1*28
R2: 28 = 2*14
R3: 28 = 4*7
Finally, we can conclude that there are only three possibilities
1- 28 by 1.
2- 14 by 2
3- 7 by4
The perimeters will be:
Perimeter 1 = 2x1 + 2x28 = 58
Perimeter 2 = 2x2 + 2x14 = 32
Perimeter 3 = 2x4+2x7 = 22
Answer:
=18
Step-by-step explanation:
