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Naddik [55]
3 years ago
10

To prove "p is equal to q" using an indirect proof, what would your starting assumption be?

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0
Assssdsssssssssssssss
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The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

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