Edge Precalculus End Behavior of Limits
1 answer:
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Answer:
A) an upper quartile of 56 and a median of 50
Step-by-step explanation:
Hello!
The lower and upper ends "box" from the box and whiskers plot is determined by the first (Q₁) and third (Q₃) quartiles of the data set and the line inside the box marks the median or second quartile of the sample (Q₂)
The length of the whiskers of the diagram is determined by the minimum value (left whisker) and the maximum value (right whisker)
If you observe the graphic:
Q₁= 42
Q₂= 50 (Median)
Q₃= 56
Min= 38
Max= 66
The box is delimited by a lower quartile of 42 and an upper quartile of 56, with a median 50, the least observation is 38 and the highest observation is 66.
The correct choice is A.
I hope this helps!
Answer:
The sum of the money shared is $1372
Step-by-step explanation:
The given ratio is
Albert:Michael:Moses=3:5:6
The total ratio is 3+5+6=14
Let the sum of money shared be $x.
Then Albert's share = 3/14 x = 3
/ 14
Michal's Share = 5x/14
If Michael received $196 more than Albert, then the difference between their share is the $196.