How do you find a coordinate on a graph by using the gradient? I also have 1 other coordinate.
1 answer:
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Well, just by looking at the beginning of the problem, Jamelia had made the common mistake of thinking that
(<span>8.4852...)
</span>is equal to
(12)
If you want to estimate a square root like 72, simply find squares that would fit around the number you are looking to find, in our case, 72.
So 9*9 is 81, which is too high and 8*8 is 64, which is too low. So you know that somewhere between those numbers is what your root of 72 is!
</span>is equal to
If you want to estimate a square root like 72, simply find squares that would fit around the number you are looking to find, in our case, 72.
So 9*9 is 81, which is too high and 8*8 is 64, which is too low. So you know that somewhere between those numbers is what your root of 72 is!
The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
![[cos(x)][tan(-x)]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5Btan%28-x%29%5D)
is the same as ![[cos(x)][ -\frac{sin(x)}{cos(x)}]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5B%20-%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5D%20)
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
5 markers -------> $6.55
4 markers -------> x