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3 years ago

Angle 1 and angle 2 are supplementary if m angle 1 is two times m angle 2 what are the measures of both angles

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

1 is 60

2 is 120

60*2 is 120

120+60=18:]

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A swimming pool is in the shape of a regular decagon. One edge of the pool is directly against the outside wall of a house. Find

Mazyrski [523]

Answer:

36 degrees.

Step-by-step explanation:

Total Sum of the Exterior Angle of a Regular Polygon $=360^0$

One Exterior Angle of a n-sided regular polygon $=\dfrac{360^0}{n}$

A decagon has 10 sides.

One Exterior Angle of a decagon $=\dfrac{360^0}{10}=36^0$

Therefore, the measure x of the angle between the house and the pool is 36 degrees.

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3 years ago

-12 ÷ 3• (-8 + (-4)2 -6) +2<br> Please help

Kipish [7]

Hi! The solution is 2(44x + 1)

Step-by-step explanation:

Divide the numbers, Multiply the numbers, add the numbers, Multiply the numbers, then find the common factor.

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1 year ago

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ale4655 [162]

Right triangle because u need to create a direct bisector

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3 years ago

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When records were first kept (t=0), the population of a rural town was 260 people. During the following years, the population gr

Firdavs [7]

Answer:

(a) The population after 15 years is 2678.

(b)Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

Step-by-step explanation:

Given that,

The population grew at a rate of

$P'(t)=45(1+\sqrt t)$

Integrating both sides

$\int P'(t) dt=\int 45(1+\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int (45+45\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int 45\ dt+\int 45\sqrt t\ dt$

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac12+1}}{\frac12+1}+c$ [ c is integration constant]

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac32}}{\frac32}+c$

$\Rightarrow P(t)= 45t+45\times\frac 23 \times {t^{\frac32}}+c$

$\Rightarrow P(t)= 45t+30 {t^{\frac32}}+c$

When t=0 , P(0)= 260

$\therefore 260= 45\times0+30\times {0^{\frac32}}+c$

$\Rightarrow c=260$

$\therefore P(t)= 45t+30 {t^{\frac32}}+260$

Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

To find the population after 15 years, we need to plug t=15 in the above expression.

$P(15)=( 45\times 15)+30( {15^{\frac32}})+260$

≈2678

The population after 15 years is 2678.

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3 years ago

19-2(3x-1) divided by 5 = x +2

VladimirAG [237]

Equation: 19-2(3x-1)/5 = x + 2

Solution:

1. Find x

(5) - 2 = (x + 2) - 2

x = 3

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3 years ago