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Masteriza [31]
4 years ago
10

identify and interpret the y-intercept of the equation in terms of the context of the situation?y=8x+134

Mathematics
1 answer:
nadezda [96]4 years ago
3 0

Answer:

134

Step-by-step explanation:

This equation follows y=mx+b

y = output

x = input

(In this case) 8 = slope

(In this case) 134 = y-intercept

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Step-by-step explanation:

7 0
3 years ago
Ian earns £420 a week after a 5% rise. <br> What was his pay before?
belka [17]
It turns out that 5% of 400 is 20.

(1/20)*400=20.

So Ian was being paid £400 a week before he was given a pay rise.
4 0
3 years ago
Read 2 more answers
Gia's ruler is divided into tenths of an inch. What fraction of an inch represents the greatest possible measurement error due t
miskamm [114]
The greatest measurement error s 1/10 of an inch, which is 10% of an inch.

Therefore the greatest measurement error is 1/10 or 10%.

Answer: 0.1 or 10% per inch.
4 0
3 years ago
A circle has a diameter of 26 feet. Find its circumference and area.
iogann1982 [59]

Answer: 81.64 feet

Step-by-step explanation:

Circumference of a circle = pi * diameter

Circumference of a circle = 3.14 * 26 feet

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5 0
2 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
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