Question

Please answer the question from the attachment.

Answer 1

$\frac{y^{2} - 7y + 12}{2y^{2} - 9y + 9} = \frac{y^{2} - 4y - 3y + 12}{2y^{2} - 6y - 3y + 9} = \frac{y(y) - y(4) - 3(y) - 3(-4)}{2y(y) - 2y(3) - 3(y) - 3(-3)} = \frac{y(y - 4) - 3(y - 4)}{2y(y - 3) - 3(y - 3)} = \frac{(y - 3)(y - 4)}{(2y - 3)(y - 3)} = \frac{y - 4}{2y - 3}$