Question

C(n) = 4/9(-3)^n-1 What is the 3rd term in the sequence?

Answer 1

Step-by-step explanation:

$c(n) = \frac{4}{9} ( - 3)^{n - 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{3- 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{2} \\ \\ \therefore \: c(3) = \frac{4}{9} \times 9 \\ \\ \huge{ \purple{ \boxed{\therefore \: c(3) = 4}}}$