C(n) = 4/9(-3)^n-1 What is the 3rd term in the sequence?

Mathematics

1 answer:

Yanka [14]3 years ago

8 0

Step-by-step explanation:

$c(n) = \frac{4}{9} ( - 3)^{n - 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{3- 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{2} \\ \\ \therefore \: c(3) = \frac{4}{9} \times 9 \\ \\ \huge{ \purple{ \boxed{\therefore \: c(3) = 4}}}$

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What is a simpler form of the expression? -3(-4y+3)+7y please explain, i don’t understand it.

Pavlova-9 [17]

Answer:

19y - 9

Step-by-step explanation:

We can use the acronym PEMDAS. First, we need to calculate -3(-4y+3) by distributing. This is -3 * (-4y) + (-3) * 3 = 12y - 9 so the expression becomes 12y - 9 + 7y. Next, we need to combine like terms. 12y and +7y are like terms since they both have y so combining them gives us 12y + 7y = 19y. -9 stays by itself since there are no other constants so the final answer is 19y - 9.

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3 years ago

Read 2 more answers

Find the TWO integers whos product is -12 and whose sum is 1<br>

Deffense [45]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$