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mojhsa [17]
3 years ago
10

The answer is not B? Please Help!!!

Mathematics
2 answers:
ryzh [129]3 years ago
7 0

Answer:

\left[\begin{array}{cc}a_{1}&a_{2}\\a_{3}&a_{4}\end{array}\right] * \left[\begin{array}{cc}b_{1}&b_{2}\\b_{3}&b_{4}\end{array}\right] = \left[\begin{array}{cc}(a_{1} * b_{1} + a_{2}* b_{3})&(a_{1} * b_{2} + a_{2} * b_{4})\\(a_{3} * b_{1} + a_{4} * b_{3})&(a_{3} * b_{2} + a_{4} * b_{4})\end{array}\right]

Plugging in the values from the two matrices will give us the answer A

bija089 [108]3 years ago
4 0

Answer: The correct option is A

Step-by-step explanation:

The transpose of a matrix is the matrix formed by interchanging the rows with the columns. It means that the transpose of matrix A would be

5 3

2 - 1

By multiplying, we would multiply the terms in each row by the corresponding terms in the columns and add.

The product of matrix A and its transpose would be

5 2 × 5 3

3 - 1 2 - 1

It becomes

25 + 4 15 + (- 2)

15 - 2 9 + 1

The final answer is

29 13

13 10

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Muiltple Answers
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4 years ago
A right triangle has a side with length 12 in and a hypotenuse with length 20 in. find the length of the missing leg. (round to
OLEGan [10]
Let the unknown side be "z" inches
Through pythagoras:
{12}^{2}  +  {z}^{2}  =  {20}^{2}
Because the square of the two sides add up to the square of the hypotenuse in a right triangle.

This means that
{z }^{2}  = {20}^{2}  -  {12}^{2}
{z}^{2}  = 400 - 144 = 256
z =  \sqrt{256}  = 16
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Hope this helped
6 0
4 years ago
(05.05)The width of a rectangle is shown below:
Ket [755]

Answer:

no idea sorry!!

Step-by-step explanation:

i think its the third but not sure

4 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
3 years ago
Find the hcf by long division method 434 ,775​
almond37 [142]

Answer:

775=434×1+341

Step-by-step explanation:

this is the answer

3 0
3 years ago
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