3 years ago

CAN SOMEONE PLEASE SOLVE THIS????????

1 answer:

defon3 years ago

3 0

Which one question? there is multiple in there.

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Airida [17]

$x+8=8x\\
7x=8\\
x=\frac{8}{7}$

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AysviL [449]

No there are 3 feet in a yard

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3 years ago

drek231 [11]

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

$58-10x\leq20+9x$

Then, add $10x$ to both sides:

$58-10x+10x\leq20+9x+10x\\58\leq20+19x$

Next, subtract $20$ from both sides:

$58-20\leq20-20+19x\\38\leq19x$

Finally, divide both sides by $19$ :

$\frac{38}{19}\leq\frac{19x}{19}\\2\leq x$

$x\geq 2$

Therefore: the answer to this inequality/equation is: x≥2

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3 years ago

Taya2010 [7]

Five less than a number n

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3 years ago

otez555 [7]

Positive product:
(-2/5)(-2/5)
(2/5)(2/5)

negative product:
(-2/5)(2/5)
(2/5)(-2/5)

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4 years ago