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Anarel [89]
3 years ago
10

What is 88/9in a fraction

Mathematics
2 answers:
Allushta [10]3 years ago
8 0
88/9 in a simplified form = 9 7/9
vitfil [10]3 years ago
5 0
I think 88/9 is a fraction if you looking for a mixed number it will be 9 7/9.
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What is the difference between the mean and the median of the following distribution?
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First you find the median which is 4. The mean is calculated by the sum of the distribution divided by the amount of numbers in the distribution (20). The mean comes out to be 4.35. Subtract 4.35 from 4 and your answer is .35.
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PLZ HELP!!!!!!!!! IM BEING TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mars2501 [29]

Answer:

B. 40

Step-by-step explanation:

It looks like a 90-degree angle so...

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3 years ago
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ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

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3 years ago
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hey!

Answer: 120:7

Hope this helps!

~LENA~

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4 years ago
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