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swat32
4 years ago
14

How do change 0.9 in fraction

Mathematics
2 answers:
yarga [219]4 years ago
6 0
You change it to 9/10
Fantom [35]4 years ago
3 0
0.9 as a fraction is: \frac{9}{10}

What place is the '9' in? It's in the tenth place.
0.9 can be said as nine \ tenths

Nine(9) tenths(10) = \frac{9}{10}
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Solve 6k + 9 &gt; k – 1.<br><br> k &gt; -3<br><br> k &gt; -5<br><br> k &gt; -4<br><br> k &gt; -2
Pavel [41]

6k + 9 > k - 1 \\ 5k >  - 10 \\ k >  - 2
6 0
3 years ago
For the x-values 1, 2, 3, and so on, the y-values of a function form an
o-na [289]

Answer: exponential decay

Step-by-step explanation:

6 0
3 years ago
2x^3-x^2+x-2 factorize​
bekas [8.4K]

Answer:

(x-1)(2x^2+x+2)

Step-by-step explanation:

Factorize:

f(x)=2x^3-x^2+x-2

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

4 0
2 years ago
Read 2 more answers
A line passes through the points (2,21) and (8,27). Write a linear function rule in terms of x and y for
tatiyna
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
6 0
2 years ago
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Raul picks 20 flowers from his mother's garden. One fourth of them are purple. How many of the flowers are purple?
steposvetlana [31]
25% were purple and 30 percent another color
8 0
4 years ago
Read 2 more answers
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