All categories

3 years ago

Pleaseee help meeeeee

Mathematics

1 answer:

sveta [45]3 years ago

7 0

5x28.3
So b I think
Hope this helps

You might be interested in

7 - 9 + (9 - 5)^2-4x 6/-6+8-3x10? Can y'all help me? I know I just asked but I'm really bad at math!!!!

Butoxors [25]

Answer:

7 - 9 + (9 - 5)^2 - 4 (-6/6) + 8 - 3×10

-4

8 0

2 years ago

Use the elimination method to solve the system of equations -x+5y=-4 and 4x+3y=16

jenyasd209 [6]

Answer:

A.(4,0)

Step-by-step explanation:

APEX

7 0

2 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

2 years ago

Find the product. (y^3)^2 * y^7

Natasha_Volkova [10]

Firstly, let's take first factor:
(y^3)^2 = y^(3*2) = y^6
and then:
y^6 * y^7 = y^(6 + 7) = y^13

8 0

2 years ago

A recent survey found that 70% of all adults over 50 wear

lubasha [3.4K]

Answer:

There is an 84.97% probability that at least six wear glasses.

Step-by-step explanation:

For each adult over 50, there are only two possible outcomes. Either they wear glasses, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 10, p = 0.7$

What is the probability that at least six wear glasses?

$P(X \geq 6) = P(X = 6) + `P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.8497$

There is an 84.97% probability that at least six wear glasses.

5 0

3 years ago