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2 years ago

7

A furniture store pays $210 to stock a coffee table. It sells the table with a 60% markup. What is the selling price of the coff

ee table?

1 answer:

koban [17]2 years ago

8 0

Answer: $336
explanation: 60% is equal to .6 so just take $210 and multiply that by .6 to get $126. Now, just take $126 and add it to $210 and you have $336.

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A similarity transformation maps polygon ABCD to polygon PQRS. If the length of is 6 and the length of the corresponding side, ,

grigory [225]

For this case, what we must do is find the scale factor.
We have then that the scale factor is given by:
$k = \frac{L1}{L2}$
Where,
L1: side length of polygon ABCD
L2: side length of polygon PQRS
Note: both sides belong to the same side of each polygon
Substituting the values we have:
$k = \frac{6}{12}$
Rewriting we have:
$k = \frac{1}{2}$
Answer:
The scale factor of dilation is given by:
$k = \frac{1}{2}$

3 0

3 years ago

Read 2 more answers

Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

6 0

3 years ago

What is (6.89+14.52)+(-14.52)???

MrRa [10]

The answer is 6.89 because
6.89+14.52=21.41
So 21.41+(-14.52)=6.89

7 0

3 years ago

Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for d<em>y</em>/d<em>x</em> :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If <em>y</em> ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago

Select all the expressions that equal 6-10,

alukav5142 [94]

Answer:

what are the expressions?

Step-by-step explanation:

6 0

2 years ago