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Anni [7]
3 years ago
14

Express answer in exact form. Show all work for full credit. A segment of a circle has a 120 arc and a chord of 8in. Find the ar

ea of the segment.

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0

Answer:

21 & 1/3 pi in.^2 - 16 sqrt 3 in.^2

Step-by-step explanation:

First, make a triangle with the chord by drawing two other lines. Each line should have an endpoint of the chord and the circle's center point. This, plus the segment, will give you a sector.

Next, bisect the chord in half with a line that has one point as the midpoint of the chord and the other point as the bisector of the central angle. This makes two 30-60-90 right triangles. This also means that now you can find out the radius of the circle by using the rules for 30-60-90 right triangles.  

You already know the long leg of the right triangle: 4 sqrt 3. From this, you can figure out that the short leg is 4 and the hypotenuse is 8.  

Now you can find out the area of the whole circle by using the formula for the area of a circle: A = pi * r^2 ----> A = 64 pi.  

Then, to find the area of the sector, you take 120o (o = degree sign) and divide it by 360o. So --> 120/360. You should get 1/3. Multiply 1/3 by the area of the circle (in this case 64 pi). So you would get 21 & 1/3 pi for the area of the sector.  

Now you need to find the area of the triangle. Use the formula for the area of triangles: A = 1/2 * b * h. We already know the base and height: back to the 30-60-90 right triangle ---> the short leg, or the height, is 4. The base was given: 8 sqrt 3. So, plug these numbers into the formula for triangles  ---> A = 1/2 * 8 sqrt 3 * 4  ---> A = 2 * 8 sqrt 3  ---> A = 16 sqrt 3.  

Finally, to find out the area of the segment, you would need to do the area of the sector minus the area of the triangle:

<u>21 & 1/3 pi in.^2 - 16 sqrt 3 in.^2</u>

<em>Hope this helps!  :)</em>

Elenna [48]3 years ago
4 0
Check the picture below.

bear in mind that, arcs get their angle measurement, from the central angle they're in.

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in a survey of 1500 people who owned a certain type of car, 1050 said they would buy that type of car again. what percent of the
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2 years ago
Find the y-intercept of the following equation. Simplify your answer.<br> y = -10x -3/7
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2 years ago
The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

6 0
3 years ago
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