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Masteriza [31]
2 years ago
10

What is true of an equilateral triangle? Two of its side lengths are equal. All its side lengths are equal. None of its side len

gths are equal. None of its interior angles are equal. What is true of an equilateral triangle ? Two of its side lengths are equal . All its side lengths are equal . None of its side lengths are equal . None of its interior angles are equal .​
Mathematics
1 answer:
KIM [24]2 years ago
4 0

Answer:

<u><em>All its side lengths are equal </em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>(and all the agle of 60°)</em></u>

<u><em></em></u>

<u><em></em></u>

Step-by-step explanation:

What is true of an equilateral triangle? Two of its side lengths are equal. <u><em>All its side lengths are equal</em></u>. None of its side lengths are equal. None of its interior angles are equal. What is true of an equilateral triangle ? Two of its side lengths are equal . All its side lengths are equal . None of its side lengths are equal . None of its interior angles are equal .​

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What is the length of BC , rounded to the nearest tenth?
Arte-miy333 [17]

Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

we have

AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

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Step-by-step explanation:

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Step-by-step explanation:

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