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3 years ago

Gabby says that 8 is a common multiple of 16 and 24. Mark says that 8 is a common factor of 16 and 24. Who is correct?

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

gabby is correct

Step-by-step explanation:

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Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)

muminat

Question:

Factor $64-x^2$

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: $(8+x)(8-x)$ is the factor

Explanation:

Given that the expression is $64-x^2$

We need to find the factor of the given expression.

Let us rewrite the expression as $8^2-x^{2}$

Since the expression is of the form $a^2-b^2$ , let us use the identity $a^2-b^2=(a+b)(a-b)$

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

$8^2-x^{2}=(8+x)(8-x)$

Thus, the factor of the expression is $(8+x)(8-x)$

Hence, Option B is the correct answer.

4 0

3 years ago

How do I expand<br> 3(2y+1)

frozen [14]

Answer:

Answer is 6y+3

Step-by-step explanation:

The working step is at the diagram above:))

Thanks for moderators for helping me with my answer:))

4 0

3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

The answer to this question

kirill115 [55]

Answer:

Step-by-step explanation:

m+m+m+m

There is an implied 1 in front of each term

1m+1m+1m+1m

Factor out the m

(1+1+1+1)m

6 0

3 years ago

PLESE HELP REPORT CARD TOMORROW Elana grew 15 flowers with 3 seed packets how many seed packets does Elana need to have a total

Andre45 [30]

15flowers/3seedpackets
5 flowers/seed packet
*4
————————————
20 follows equals 4 seed packets
your answer is ——-^^^^^^^^^^^^^^^

5 0

3 years ago

Read 2 more answers