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Mademuasel [1]
3 years ago
10

-k-(-8k) I need an answer

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0

Answer:

9.66453964 × 10-23 m2 kg s-2 K-1

Step-by-step explanation:

alexira [117]3 years ago
5 0

(-k) - ((-8) * k) =

9.66453964 × 10-23 m2 kg s-2 K-1

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Crying cloud :’)<br> Ye-
-BARSIC- [3]

crying cloud? why?????

7 0
3 years ago
The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun
Luden [163]

Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

\frac{num. of students}{sample size} * dollar spent

Therefore,

For $10:

\frac{2}{50} * 10 = 0.4

For $8:

\frac{1}{50} * 8 = 0.16 l

For $6:

\frac{12}{50} * 6 = 1.44

For $5:

\frac{23}{50} * 5 = 2.3

For $4:

\frac{8}{50} * 4 = 0.64

For $3:

\frac{4}{50} * 3 = 0.24

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0
3 years ago
F(1)=7, f(n)=-4*f(n-1)+15
bezimeni [28]

it equals 7

Hope this helps

3 0
4 years ago
When drawing a line of best fit do you consider the outliers apart of the data
swat32

Answer:

No i don't think you do.

Explanation:

Hope this helps! :)

7 0
4 years ago
A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank
ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = (3.78541)(1000) ml = 3785.41 ml.

13.4 gallon = (3785.41)(13.4) ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = \frac{x}{50724.494}

So we can write,

0.737 =\frac{x}{50724.494}

To find x we will multiply both sides by 50724.494. we will get,

(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)

(0.737)(50724.494) = x

37383.95 = x

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

5 0
4 years ago
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