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Stolb23 [73]
4 years ago
11

Four horses are pulling a wagon. Each horse drinks 45000 ml of water each day. How many liters of water will the horses drink in

5 days?
Mathematics
1 answer:
s2008m [1.1K]4 years ago
3 0

45000 x 4 = 180,000

180,000 * 5 = 900,000 ml in 5 days

1 liter = 1000 ml

900,000 / 1000 = 900 liters of water

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Please help me with this!! I will mark brainlist!!
kondor19780726 [428]

Answer:

54°

Step-by-step explanation:

Your triangle is isosceles. You have been given the third angle, and you have been asked to find the measure of one of the two equal angles. We know that the internal angles of a triangle sum to 180, so 72+x+x=180 \rightarrow 2x=108 \rightarrow x = 54

3 0
3 years ago
The probability that a plane departs on time at a certain airport is .87 The probability that a plane arrives on time given it d
sleet_krkn [62]

Answer:

0.9355

Step-by-step explanation:

What we will use here is conditional probability formula.

let A be the event that the plane departs on time

and B be the event that it arrives on time

P(A) = 0.87

P(B|A) = 0.93

P(B) = ?

P(A n B) = ?

Mathematically;

P(B|A) = P(B nA)/P(A)

0.93 = 0.87/P(A)

P(A) = 0.87/0.93

P(A) = 0.935483870967742

which is 0.9355 to four decimal places

7 0
3 years ago
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erik [133]
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5 0
3 years ago
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SashulF [63]

The Solution.

The given equation is

\begin{gathered} y=|x|+7 \\ \text{Where x=11} \end{gathered}

Substituting 11 for x, we can get the value of y.

\begin{gathered} y=|11|+7 \\ y=11+7 \\ y=18 \end{gathered}

Hence, the value of y is 18.

5 0
1 year ago
A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de
marin [14]

Answer:

\frac{23}{4} feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 \frac{1}{2} feet

                                                                             =   \frac{5}{2} feet

The depth of the fish to its initial position at 4:00 pm = 3 \frac{1}{4} feet

                                                                              = \frac{13}{4} feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =  \frac{5}{2} + \frac{13}{4}

                                        = \frac{10 + 13}{4}

                                         = \frac{23}{4}

The position of the fish with respect to the water's surface at 4:00 pm is \frac{23}{4} feet.

8 0
3 years ago
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