Question

7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 to the negative 4th power times 2 to the 3rd power

Answer 1

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

$\frac{x^a}{x^b}=x^{a-b}$

$x^0=1$

$(x^a)(x^b)=x^{a+b}$

$x^{-a}=\frac{1}{x^a}$

$\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=$

$\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=$

$\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=$

$(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=$

$(7^{-5-(-5)})(2^{0-3})=$

$(7^0)(2^{-3})=$

$\frac{1}{2^3}=$

$\frac{1}{8}$