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3 years ago

PLEASE ANSWER WITHIN TWENTY MINUTES!!

Mathematics

1 answer:

Nataly [62]3 years ago

6 0

3) <3 = <4 .....> Vertical angles are congruent

Answer is B.<3 = <4

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7. The revenue, in dollars, that eMathInstruction makes off its videos in a given day depends on how many views they receive. If

Scilla [17]

Answer:

Step-by-step explanation:

Since x is counted in hundreds, x=600/100.

x=6

6x-10

When you substitue,

6*6-10

36-10

you get 26.

5 0

3 years ago

What is 87/297 in simplest form??

castortr0y [4]

Answer:

Reduce 87/297 to lowest terms

The simplest form of 87297 is 2999.

4 0

3 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

Find the value of AC

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

Find the value of BC

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

Find the value of BD

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

the answer is

the length of BD is 11.93 units

8 0

3 years ago

Read 2 more answers

Can someone tell me what the intersection on the line is ??

algol13

The intersection is at (2,-1)

7 0

3 years ago

Read 2 more answers

A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba

masha68 [24]

In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.

W = Fd

The total force is
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be

W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J

5 0

3 years ago