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Rus_ich [418]
3 years ago
8

If you cross multiply to solve the proportation x/10=6/29, which equation could you use to solve the proportation?

Mathematics
1 answer:
musickatia [10]3 years ago
4 0
X/10 = 6/29
cross multiply
29x = (6)(10)...answer D
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Hello!
Gnesinka [82]

Answer:

  • A. 2 < x < 10

Step-by-step explanation:

With two congruent sides the third side is greater against a greater angle.

<u>34 < 36, therefore:</u>

  • 3x - 6 < 24
  • 3x  < 30
  • x < 10

<u>And, the angle should have a positive value:</u>

  • 3x - 6 > 0
  • 3x > 6
  • x > 2

<u>Combined, we get:</u>

  • 2 < x < 10
8 0
3 years ago
???? please help lol
kow [346]

Answer:

  1. 150π ft²
  2. 10π ft.

Step-by-step explanation:

Area of the sector :

Area (sector) = \pi r^{2} \times \frac{\theta}{360^{o}}

Finding the area given r = 30 ft. and θ = 60° :

⇒ Area = π × (30)² × 60/360

⇒ Area = π × 900/6

⇒ Area = 150π ft²

===========================================================

Length of the arc :

Length (arc) =2 \pi r} \times \frac{\theta}{360^{o}}

Finding the arc length given r = 30 ft. and θ = 60° :

⇒ Arc Length = 2 × π × 30 × 60/360

⇒ Arc Length = 60/6 × π

⇒ Arc Length = 10π ft.

7 0
1 year ago
Read 2 more answers
If 1 cost 9p find the cost of 100
damaskus [11]
9p times 100 = 900p or £9
7 0
3 years ago
7m - 17 = -24<br> what is m?
aev [14]

Answer:

Move all terms that don't contain

m

to the right side and solve.

Exact Form:

m

=

41

7

Decimal Form:

m

=

5.

¯¯¯¯¯¯¯¯¯¯¯¯

857142

Mixed Number Form:

m

=

5

6

7

Tap to view steps...

3 0
2 years ago
Find the slope of a line perpendicular to 2x-y-16
Alekssandra [29.7K]

put the equation 2x - y = 16 in the form of y = mx + c

2x - y = 16

2x = 16 + y

y = 2x - 16

the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.

you can form this equation with that info

2x = -1

x = -1/2

OR

you can flip and change the sign (numerator) of 2/1

2/1

= -1/2

6 0
3 years ago
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