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Mekhanik [1.2K]
3 years ago
5

Solve the following equation for x. Express your answer in the simplest form.

Mathematics
1 answer:
kumpel [21]3 years ago
6 0

Expressions are arithmetical declarations that have at least two terms that contain figures or factors but which are linked by an intermediate operator. Adding, subtraction, multiplication, or division may well be the mathematical operators, and the further discussion can be defined as follows:

Given:

\to \bold{4 -\frac{1}{2}(-8x + 6) = -5x - (-x + 10)}\\\\

To find:

\bold{x=?}\\\\

Solution:

\to \bold{4 -\frac{1}{2}(-8x + 6) = -5x -(-x + 10)}\\\\\to \bold{4 +\frac{8x}{2} -  \frac{6}{2} = -5x +x - 10}\\\\\to \bold{4 +4x -3 = -5x +x - 10}\\\\\to \bold{4 +10 +4x +5x -x -3 = 0}\\\\\to \bold{11 +8x  = 0}\\\\\to \bold{8x  = -11}\\\\\to \bold{x  =\frac{-11}{8}}\\\\

So, the final answer is "\bold{x  =\frac{-11}{8}}".

Learn more:

brainly.com/question/13413561

You might be interested in
Which value is a solution to the inequality x < 4?
densk [106]
The answer is x > 4.5.

Explanation:

-24 > -6(x - 0.5)

-24 > -6x + 3

6x > 3 + 24

6x > 27

x > 27/6

x > 4.5

Hope this helps :)
3 0
3 years ago
Graph each of the equations and then determine which one represents the rank catcher that is elevated
Tanya [424]
We have two functions that are Parabolas. A parabola is a type of quadratic function which is a special type of “U”-shaped curve called. So let's solve this problem for the first parabola and then for the second one.

1. Graph of the first equation

We have that:

y=x^2-2x+3

So if we graph this equation, the parabola that matches it is shown in Figure 1.

1.1 Direction of Parabola

In general, a parabola or quadratic function is given by the following way:

y=ax^2+bx+c \\ \\ where \ "a" \ is \ called \ the \ leading \ coefficient

Given that our leading coefficient is positive, then the direction of the parabola is upward, that is, it opens upward.

1.2 Location of vertex with respect to the x-axis

The vertex a parabola can be found as follows:

(-\frac{b}{2a},f(-\frac{b}{2a}))

But: \\ \\ a=1 \\ b=-2 \\ c=3 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{(-2)}{2(1)}=1 \\ \\ f(1)=1^2-2(1)+3=2 \\ \\ So \ the \ vertex \ is: \\ \\ V(1,2)

So the vertex is located two units above the x-axis.

<span>1.3 Determine if the graph depicts the rain gauge
</span>
A rain gauge is an instrument used by meteorologists and hydrologists to gather and measure the amount of liquid precipitation<span> over a set period of time.
</span>
From Figure 4 we can affirm that this is the parabola that resembles a rain gauge elevated from the ground. 

1.4 Why or why not?

It basically the question asks for the parabola that has a vertex well above the x-axis. From Figure 4, you can see that the elevated parabola is in fact:

y=x^2-2x+3

2. Graph of the second equation

We have that:

y=x^2+4x+4

So if we graph this equation, the parabola that matches it is shown in Figure 2.

2.1 Direction of Parabola

As in the previous problem, given that our leading coefficient is positive, then the direction of the parabola is also upward, that is, it opens upward.

2.2 Location of vertex with respect to the x-axis

The vertex of a parabola can be found as follows:

(-\frac{b}{2a},f(-\frac{b}{2a}))

In \ this \ case: \\ \\ a=1 \\ b=4 \\ c=3 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{4}{2(1)}=-2 \\ \\ f(-2)=(-2)^2+4(-2)+4=0 \\ \\ So \ the \ vertex \ is: \\ \\ V(-2,0)

So the vertex lies on the x-axis.

2.3 Determine if the graph depicts the rain gauge

This parabola does not resembles a rain gauge elevated from the ground.

2.4 Why or why not?

As you can see the parabola touches the x-axis. If the x-axis represents the ground, then the rain gauge is touching it, that is, it is not elevated.

3. Graph of the third equation

We have that:

y=3x^2+21x+30

So if we graph this equation, the parabola that matches it is shown in Figure 5.

3.1 Direction of Parabola

As in the previous parabolas, given that our leading coefficient is positive, then the direction of the parabola is also upward, that is, it opens upward.

3.2 Location of vertex with respect to the x-axis

In \ this \ case: \\ \\ a=3 \\ b=21 \\ c=30 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{21}{2(3)}=-\frac{7}{2} \\ \\ f(-\frac{7}{2})=3(-\frac{7}{2})^2+21(-\frac{7}{2})+30=-\frac{27}{4} \\ \\ So \ the \ vertex \ is: \\ \\ V(-\frac{7}{2},-\frac{27}{4})

So the vertex is shifted \frac{27}{4} units downward the x-axis.

3.3 Determine if the graph depicts the rain gauge

This parabola does not resembles a rain gauge elevated from the ground.

3.4 Why or why not?

The vertex of this parabola lies on the negative y-axis. So it is not elevated from the ground.

5 0
3 years ago
I need to find the area of the shaded region, can anyone explain how to do it? ​
vesna_86 [32]

Answer:

Step-by-step explanation:

JM is a diameter. 1/2 JM is the radius. 1/2 10 = 5

The radius is 5

The above statement is true if N is the center.

The semi circle has an area of pi r^2/2 = 5^2/2 * pi = 25/2 * pi

12.5 pi

The area of the other part is

(58/360) * pi * r^2 =

0.161 * pi * 5^2

0.161 * pi * 25

4.03 * pi

Now add these two parts together.

12.5pi + 4.03= 16.53 * pi.

That's one possible answer.

Another would be 16.53 * 3.14 = 51.897

If you have choices, list them.

5 0
3 years ago
What equation results from completing the squre and then factoring x^2+10=15
nlexa [21]

For this case we must complete squares:

x ^ 2 + 10x = 15

We add the square of half the coefficient of the term "x",

(\frac {b} {2a}) ^ 2 on both sides of the equation:

x^2+10x+(\frac {10} {2 (1)}) ^ 2 = 25 + 15\\x ^ 2 + 10x + 5 ^ 2 = 25 + 15

According to the perfect square trinomial we have:

(a + b) ^ 2 = a ^2 + 2ab + b ^ 2

Rewriting the expression we have:

a = x\\b = 5\\(x + 5) ^ 2 = 25 + 15\\(x + 5) ^ 2 = 40

ANswer:

(x + 5) ^ 2 = 40

6 0
3 years ago
Expand And Simplify The Following:
Georgia [21]
For all the questions, we will be using the FOIL pattern.
1. (x+3)(x-3)(3x+2)
(x^2-3x+3x-9)(3x+2)
(x^2-9)(3x+2)
3x^3+2x^2-27x-18
2. (2x+1)(x-2)(x+3)
(2x^2-4x+x-2)(x+3)
(2x^2-3x-2)(x+3)
2x^3+3x^2-11x-6
3. (x-3)(2x+1)(3x-2)
(2x^2+x-6x-3)(3x-2)
(2x^2-5x-3)(3x-2)
6x^3-19x^2+x+6
Hope this helped!
8 0
3 years ago
Read 2 more answers
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