Answer:
year 6.6025 if there is no typo in your question and numbers are right.
Step-by-step explanation:
G = 63205 + 2500x
S = 50000 + 4500x
since 9% of 50000 = 0.09(50000) = 4500
find when G = S
63205 + 2500x = 50000 + 4500x
subtract both sides by 2500x to move x terms to the right
63205 = 50000 + 2000x
subtract both sides by 50000 to move the number to the left, so we can get like terms on each side
13205 = 2000x
divide both sides by 2000
x = 6.6025
This question seems to be a good example of why we need to learn math!
P=present value
i=interest rate = 0.02 per year
time, t=1 year
we need P such that
interest = Pit ≥ 9.99
or
P(.0002*1) ≥ 9.99
=>
P ≥ 9.99/0.0002 = 49950
Answer: it takes a minimum balance of $49950 to cover a "below minimum balance fee" of $9.99.
Answer:
1.) 8.09g ; 2) 206.7 years
Step-by-step explanation:
Given the following :
Half-life(t1/2) of Uranium-232 = 68.9 years
a) If you have a 100 gram sample, how much would be left after 250 years?
Initial quantity (No) = 100g
Time elapsed (t) = 250 years
Find the quantity of substance remaining (N(t))
Recall :
N(t) = No(0.5)^(t/t1/2)
N(250) = 100(0.5)^(250/68.9)
N(250) = 100(0.5)^3.6284470
N(250) = 100 × 0.0808590
= 8.0859045
= 8.09g
2) If you have a 100 gram sample, how long would it take for there to be 12.5 grams remaining?
Using the relation :
N / No = (1/2)^n
Where N = Amount of remaining or left
No = Original quantity
n = number of half-lifes
N = 12.5g ; No = 100g
12.5 / 100 = (1/2)^n
0.125 = (1/2)^n
Converting 0.125 to fraction
(1/8) = 1/2^n
8 = 2^n
2^3 = 2^n
n = 3
Recall ;
Number of half life's (n) = t / t1/2
t = time elapsed ; t1/2 = half life
3 = t / 68.9
t = 3 × 68.9
t = 206.7 years
Answer: C=25.12
Step-by-step explanation:
