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MA_775_DIABLO [31]
3 years ago
12

-5x+35=40what are the steps?​

Mathematics
2 answers:
Svetlanka [38]3 years ago
7 0

Answer:

Step-by-step explanation:

-5x + 35 = 40

Subract 35 from both sides -5x + 35 - 35 = 40 - 35  = (-5x = 5)

Divide -5 from both sides -5x / -5 = 5 / -5 =

x = -1

ELEN [110]3 years ago
3 0

Answer:

x= -1

Step-by-step explanation:

First subtract 35 from both sides to get -5x by itself:

-5x+35=40

-35       -35

-5x=5

Then divide by -5:

\frac{-5x}{-5} = \frac{5}{-5}

x=-1

Hope this helps! :)

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Given this number line, ab=
Nastasia [14]

Answer:

3

Step-by-step explanation:

7 -4 = 3

5 0
3 years ago
A clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood. He randoml
lidiya [134]

Answer:

No, there is not any sufficient evidence to conclude that individuals who have experienced childhood trauma have lower self-efficacy in adulthood.

Step-by-step explanation:

We are given that a clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood.

He randomly selects 22 adults who have experienced childhood trauma and finds that their mean self-efficacy score equals 118.1.

Self-efficacy scores in the general population of adults are distributed normally with a mean equal to 118.5 and a standard deviation equal to 18.8 .

<em>Let </em>\mu<em> = mean self-efficacy score.</em>

So, Null Hypothesis, H_0 : \mu \geq 118.5      {means that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood}

Alternate Hypothesis, H_A : \mu < 118.5    {means that the individuals who have experienced childhood trauma have lower self-efficacy in adulthood}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                      T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean self-efficacy score = 118.1

            \sigma = population standard deviation = 18.8

          n = sample of adults who have experienced childhood trauma = 22

So, <u><em>test statistics</em></u>  =  \frac{118.1-118.5}{\frac{18.8}{\sqrt{22} } }  

                              =  -0.0998

The value of z test statistics is -0.0998.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical value of -1.645 for left-tailed test.</u>

Since our test statistic is more than the critical value of z as -0.0998 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood.

4 0
4 years ago
Can someone help me on this work
finlep [7]
Properties of rhombus:
1. All the sides are equal
2. Opposite angles are equal
3. Diagonal bisect each other at right angle.
4. Diagonal bisects the angle of the rhombus.

Hope you can solve the questions now:)
3 0
3 years ago
Suppose that, during the first year after its hatching, the weight of a duck increases at a rate proportional to its weight. The
krok68 [10]

Answer:

4.25 pound

Step-by-step explanation:

Ratio is the quantitative relation between two amounts, which is being compared. In this question we are considering the ratio of weight to time consumed.

At the age 0

Weight = 2 pound

At the age 4 months

Weight = 3.5 pound

Proportion of Change = Change in Weight / Change in time = (3.5 - 2) / (4-0) = 1.5 / 4 = 0.375 pound per month

Weight after 6 months = 2 + (6 x 0.375 pond per month )= 4.25 pound

4 0
4 years ago
(fog) f(x) = 1/x g(x) square root x+3
NeX [460]

Answer:

see the step below, but I'm not sure if this you want

Step-by-step explanation:

(fog) =  \frac{1}{ \sqrt{x + 3} }

(fog) =  \frac{ \sqrt{ x  + 3} }{x + 3}

3 0
2 years ago
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