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jeka57 [31]
3 years ago
15

What it the value of 2^(-1)

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
The answer to your question is .5
Svet_ta [14]3 years ago
5 0
The value of 2^(-1) is 0.5
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Maria needs to buy cat food. At Save Rite, cat food costs $5.25 for 3 cans. Spend Less offers cat food at $7.50 for 5 cans. Mari
ozzi

Answer:

C

Step-by-step explanation:

First, in order to find the lowest price, you have to find the cost for 1 can in each store.

Save Rite: Since it is $ 5.25 for 3 cans, you divide 5.25 by 3. The quotient is 1.75. So, the price is $ 1.75 per can.

Then you do the same for Spend Less.

Spend Less: Since it is $ 7.50 for 5 cans, you divide 7.5 by 5. The quotient is 1.5. So, the price is $ 1.50 per can.

Since Save Rite's price for one can is $ 0.25 more than Spend Less, it is more expensive.  

So in order to see how much she paid for 15 cans from the cheapest store, you would have to multiply 15 by 1.5.

The answer is 22.50.

The answer is C

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3 years ago
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Write 12 as a percentage of 15.
aivan3 [116]

Answer:

80

now enjoy your answer.

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3 years ago
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4x + 1 = 2x-5 HELP QUICKKKKKKKKKKKKKKK
V125BC [204]

Answer:

4x_2x=_5_1

2x=_6

2x/2=_6/2

X=_3

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Find the missing number: 33, 24, ?, 3
OlgaM077 [116]

Answer:

in sequences of 3, 5, 8, 11 and all multiplied by 3 so 15 is the missing number

7 0
4 years ago
A motorboat travels 172 km in 3 hours going upstream and 372 in 4 hours going downstream. What is the rate of the boat in still
torisob [31]

Answer:

<em>The rate of the boat is 75.17 km/h and the rate of the stream is 17.83 km/h</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

B = speed (rate) of the boat in still water

S = speed (rate) of the stream

The boat travels 172 km in 3 hours when going upstream, that is when the speed of the stream subtracts its own speed. The speed is the distance divided by the time, thus:

\displaystyle B-S=\frac{172}{3}

Multiplying by 3:

3B - 3S = 172        [1]

The boat travels 372 km in 4 hours downstream when the speed of the current adds to its own:

\displaystyle B+S=\frac{372}{4}=93

B + S = 93

Solving for B:

B = 93 - S       [2]

Substituting in [1]

3(93 - S) - 3S = 172

Operating:

279 - 3S - 3S = 172

279 - 6S = 172

Subtracting 279:

- 6S = 172 - 279

- 6S = -107

Multiplying by -1 and solving for S:

S = \frac{107}{6}\approx 17.83\ km/h

From [2]:

B = 93 - \frac{107}{6}

B=\frac{451}{6}\approx 75.17\ km/h

4 0
3 years ago
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