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oksian1 [2.3K]
3 years ago
8

What is the explicit formula for this sequence -7, -4, -1, 2, 5

Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

\large\boxed{a_n=3n-10}

Step-by-step explanation:

It's an arithmetic sequence.

-4-(-7)=-4+7=3\\-1-(-4)=-1+4=3\\2-(-1)=2+1=3\\5-2=3

The difference is constant.

The explicit formula of an arithmetic sequence:

a_n=a_1+(n-1)d

Substitute:

a_1=-7,\ d=3

a_n=-7+(n-1)(3)          <em>use distributive property</em>

a_n=-7+3n-3\\\\a_n=3n+(-7-3)\\\\a_n=3n-10

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Evaluate the function <br><br> f(x) = 3x^2 + 4x + 19<br><br> Find f(-7)
yanalaym [24]

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Step-by-step explanation:

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Please help me in this question.Tell me if it is good. And if it is not good then do it for me please.
Orlov [11]

Answer:

Y = 170, Z = 64.

Step-by-step explanation:

Since y is the external angle to x, which you got right, it is in fact, 180-10, = 170 degrees. And since z is the external to our unknown angle, that means it is equal to the sum of the other two angles in the triangle. That means z is 54 + 10, which is 64.

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3 years ago
In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

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Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

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The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

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Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

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<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0
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sveticcg [70]
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3 years ago
Find the distance between points (-3,-4) and (1,-2)
Ludmilka [50]

Answer:

√20 or 4.47 ish

Step-by-step explanation:

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√(4)²+(2)²

√16+4

√20

4.47 ish

(Hopefully this is correct, have a nice day!)

6 0
3 years ago
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