we have
![y> -3x+2](https://tex.z-dn.net/?f=y%3E%20-3x%2B2)
The solution is the shaded area above the dotted line
we know that
If a point is a solution of the inequality, then the coordinates of the point must satisfy the inequality
We will verify all cases to determine the solution of the problem
<u>Case A)</u> Point ![(0,2)](https://tex.z-dn.net/?f=%280%2C2%29)
![x=0\\y=2](https://tex.z-dn.net/?f=x%3D0%5C%5Cy%3D2)
Substitute the value of x and y in the inequality and verify
![2> -3*0+2](https://tex.z-dn.net/?f=2%3E%20-3%2A0%2B2)
-------> is not true
therefore
the point
is not a solution of the inequality
<u>Case B)</u> Point ![(2,0)](https://tex.z-dn.net/?f=%282%2C0%29)
![x=2\\y=0](https://tex.z-dn.net/?f=x%3D2%5C%5Cy%3D0)
Substitute the value of x and y in the inequality and verify
![0> -3*2+2](https://tex.z-dn.net/?f=0%3E%20-3%2A2%2B2)
-------> is true
therefore
the point
is a solution of the inequality
<u>Case C)</u> Point ![(1,-2)](https://tex.z-dn.net/?f=%281%2C-2%29)
![x=1\\y=-2](https://tex.z-dn.net/?f=x%3D1%5C%5Cy%3D-2)
Substitute the value of x and y in the inequality and verify
![-2> -3*1+2](https://tex.z-dn.net/?f=-2%3E%20-3%2A1%2B2)
-------> is not true
therefore
the point
is not a solution of the inequality
<u>Case D)</u> Point ![(-2,1)](https://tex.z-dn.net/?f=%28-2%2C1%29)
![x=-2\\y=1](https://tex.z-dn.net/?f=x%3D-2%5C%5Cy%3D1)
Substitute the value of x and y in the inequality and verify
![1> -3*(-2)+2](https://tex.z-dn.net/?f=1%3E%20-3%2A%28-2%29%2B2)
-------> is not true
therefore
the point
is not a solution of the inequality
therefore
<u>the answer is the Point B</u>
![(2,0)](https://tex.z-dn.net/?f=%282%2C0%29)
To better understand the problem see the attached figure
Answer:
answers are 3 and 62
Step-by-step explanation:
the answers were give above. If further instruction needed lmk :)
Answer:
A = 80 S =70
Step-by-step explanation:
#Adults tickets = A
#Students tickets = S
A + S = 150
5A (means the price is $5 times the number of Adult tickets) equals the total amount for all of the Adult tickets altogether
3S (means the price is $3 times the number of Student tickets) equals the total amount for all of the students tickets altogether
5A + 3S = 610 (Means adding the total of all the student tickets plus adult tickets will equal $610 for all tickets sold)
Using both equations now, you can use substitution or elimination to solve for one of the variables. Then you can use the variable to substitute to solve the remaining one.
A + S = 150
5A + 3S = 610
Substitution:
A = 150 - S (Rearrange the first equation by moving S to the other side)
Substitute into the other equation
5 (150 - S) + 3S = 610
750 - 5S + 3S = 610 Combine like terms : -2S = -140
Solve for S = 70
Substitute into A + S = 150 A + (70) = 150
A = 80
Answer:
Each pair of socks cost $4.55
Step-by-step explanation:
14*.30=4.2
14+4.2=18.2
18.2/4= 4.55