In 1910, the population of Seattle, Washington, was 237,194. In 2010, the population had grown to 608,660. By about how much did
1 answer:
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The answer is 15 in³.
The volume of the cone is:
where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone
The volume of the cylinder is:
where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone
Since <span>the cone fits exactly inside of the cylinder, they have the same radius and the height:
r</span>₁ = r₂
h₁ = h₂
Also:
V₁ = 5
Now, let's write two volume formulas together:
<span>
</span>
We can include V₂ into V₁:
⇒
The volume of the cone is:
where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone
The volume of the cylinder is:
where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone
Since <span>the cone fits exactly inside of the cylinder, they have the same radius and the height:
r</span>₁ = r₂
h₁ = h₂
Also:
V₁ = 5
Now, let's write two volume formulas together:
<span>
We can include V₂ into V₁:
⇒
Answer:
- perimeter: 46 ft
- area: 126 ft²
Step-by-step explanation:
Since the 3 ft edge is on both sides of the pool, each dimension of the pool is 6 ft shorter than the corresponding dimension of the space. The pool will be 15 ft -6 ft = 9 ft in one direction and 20 ft -6 ft = 14 ft in the other direction.
The perimeter of the pool is the sum of its side lengths:
P = 9 ft + 14 ft + 9 ft + 14 ft = 2(9 ft +14 ft) = 2(23 ft)
P = 46 ft
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The area of the pool is the product of its length and width:
A = (14 ft)(9 ft) = 126 ft²
The perimeter and area are 46 ft and 126 ft², respectively.
