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Brums [2.3K]
4 years ago
13

225 as the product of its prime factors

Mathematics
1 answer:
frutty [35]4 years ago
3 0

225:5=45\\45:5=9\\9:3=3\\3:3=1\\\\225=\boxed{5\cdot5\cdot3\cdot3}

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Steel is formed by combining masses of carbon and iron in the ratio 1:49. How many pounds of iron would it take to create 10 pou
Sergeu [11.5K]

Answer:

9.8

Step-by-step explanation:

1:49= ratio of carbon to to iron

1+49= steel

50=10pounds

49=?pounds

49 * 10/50

=49/5

=9.8pounds

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3 years ago
Please help as soon as possible
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Answer:

2.2.6

Step-by-step explanation:

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The center of a circle is at the onigin on a coordinate grd. The vertex of a parabola that opens upward is at (0, 9). If the
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4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

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If lara has 90 questions in the test, and there are 47 students in the class, how many questions are there in the whole class?​
Ivanshal [37]
4,230, which is solved by multiplying both the questions and the students
3 0
3 years ago
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