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Ivanshal [37]
3 years ago
6

I need help please .!

Mathematics
1 answer:
kvasek [131]3 years ago
7 0
For the triangle with sides 6 and x, x = 8 and scale factor is 4/3
For the triangle with sides 5 and x, x = 4 and scale factor is 4
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What is the value of x​
taurus [48]

110

180 - 70 = 110

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3 years ago
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Help! Please! <br> Factor the polynomial completely.<br> 32z^5-2z
Sever21 [200]

Answer:

2z(4z^2+1)(2z+1)(2z-1)

Step-by-step explanation:

here is just some basic polynomial factoring where you find something both the numbers have in common and you take that out of the equation. here i just went a little bit deeper and after taking out the common factor i also expanded my answer further as this would be the fully correct answer.

hope this helps!

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2 years ago
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The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
2 years ago
Need help with 18&amp;19 please help me tyvm
maks197457 [2]
The answer to question 18 is C. and the answer to question 19 is B
7 0
2 years ago
According to Internet security experts, approximately 90% of all e-mail messages are spam (unsolicited commercial e-mail), while
KonstantinChe [14]

Answer:

0.0656

Step-by-step explanation:

For each message, we have these following probabilities:

90% probability it is spam.

10% probability it is legitimate.

Compute the probability that the first legitimate e-mail she finds is the fifth message she checks:

The first four all spam, each with a 90% probability.

The fifth legitimate, with a 10% probability.

P = (0.9)^{4} \times 0.1 = 0.0656

3 0
3 years ago
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