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Tems11 [23]
3 years ago
12

A box of baseball cards is $25.00 with %15 off. What is the sale price of the box of cards? In other words, how much is it after

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

21.25

Step-by-step explanation:

you would multiply 25 by 0.15 to get the percent being taken off then subtract that from your original price

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Jane thought of a number then added -5 and subtracted -8 to get 13. What number did Jane start with
ad-work [718]
Rephrased: Jane thought of a number, subtracted 5, and added 8 to get 13. -5+8=3. 13-3=10. Jane’s number is 10.
3 0
3 years ago
What is an equation of the the line that passes through the point (3,6)and is parallel to the line 4x-3y=21
disa [49]

Answer:

y=4x/3+9/3

Step-by-step explanation:

slop is 4x/3

and the point is 3,6

so y-6 = 4x/3(x-3)

sove the you will have y=4x/3+9/3

7 0
3 years ago
Find the product of the solutions
irina1246 [14]

Answer:

A.  -41/15.

Step-by-step explanation:

15x^2 + 23x - 41 = 0

Product of the roots of ax^2 + bx + c = c/a.

Thus the product of the roots of this equation = -41/15.

7 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
An artist is deciding between two different triangular shapes to use for a sculpture. The first triangle has a base of 20 feet a
Kipish [7]
4 i belive altho  i could be way wrong
4 0
3 years ago
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