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3 years ago

13

Main street and hawthorane boulevard run parallel to each other. park avenue runs straight across town and intersects hawthorne

boulevard and main street at 90 degree angle

1 answer:

Dmitry [639]3 years ago

6 0

What's the question?

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I have to find the area of the shape

Alekssandra [29.7K]

The answer is 18m^2. if u find the area of each section and add it up together at the end then u get 18

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3 years ago

Please help! What is 9.6=1/2b show work please!

o-na [289]

Answer:

b = 19.2

Step-by-step explanation:

9.6 = ½b

=> 9.6 × (2/1) = b

=> 9.6 × 2 = b

=> 19.2 = b

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2 years ago

Please help! I’m not sure what order they go in! (7th grade math)

avanturin [10]

Answer:

30: -5, -2, | 2 |, | 3 |, 8

31: -7, -6, | 5 |, | -6 |, 8

32: -12, | 10 |, | -12 |, | -15 |, | -26 |

33: -17, | -11 |, | 20 |, 21, | -34 |

Step-by-step explanation:

The absolute value turns a negative function into a positive one.

Example: | -24 | would become 24

If it is positive, it stays the same.

Example: | 14 | would simple be 14

7 0

3 years ago

Read 2 more answers

The rectangle below has an area of x^2-x-72 square meters and a length of x+8 meters.

melamori03 [73]

Answer:

width x-9 meters

Step-by-step explanation:

(x²-x-72)÷(x+8)

= x-9

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2 years ago

How is this worked out ? im confused.

Rudik [331]

Answer:

From the given ratio for $tan\theta=\frac{4}{5}$ we found the values are

$sin\theta=4$

$cos\theta=5$

$csc\theta=\frac{1}{4}$

$sec\theta=\frac{1}{5}$

$cot\theta=\frac{5}{4}}$

Step-by-step explanation:

Given the ratio for $tan\theta=\frac{4}{5}$

We have to find the rest of trignometric functions:

$tan\theta=\frac{4}{5}\hfill (1)$

$tan\theta$ can be written as

$tan\theta=\frac{sin\theta}{cos\theta}\hfill (2)$

Comparing equations (1) and (2) we get

$tan\theta=\frac{sin\theta}{cos\theta}=\frac{4}{5}$

$\frac{sin\theta}{cos\theta}=\frac{4}{5}$

Equating the coressponding numerator and denominator respectively

Therefore $sin\theta=4$ and $cos\theta=5$

We can find $csc\theta$

$csc\theta=\frac{1}{sin\theta}$

$=\frac{1}{4}$ (since $sin\theta=4$ )

$csc\theta=\frac{1}{4}$

We can find $sec\theta$

$sec\theta=\frac{1}{cos\theta}$

$=\frac{1}{5}$ (since $cos\theta=5$ )

$sec\theta=\frac{1}{5}$

To find $cot\theta$ :

$cot\theta=\frac{1}{tan\theta}$

$=\frac{1}{\frac{4}{5}}$

$=1\times \frac{5}{4}$

$=\frac{5}{4}}$

$cot\theta=\frac{5}{4}}$

7 0

3 years ago