Answer:
Answer Below
Step-by-step explanation:
a. 2L+2W≥40
thats equal to 12+2W≥40 since it says the length is 6
That means 2W≥28
That means width ≥ 14
so the width can be 14 or greater
b. Smallest possible width is 14 because the inequality
Fter<span> a </span>125<span>% </span>markup<span> and a </span>10<span>% </span>discount<span> the </span>price<span> of a </span>watch<span> is 30.78 </span>before tax<span> what was the </span>wholesale price<span> - 2929721. ... If an item is $15.20 is increased by </span>125<span>% (34.20) it would be about $34.20 </span>before<span> we subtract </span>10<span>% (3.42)....we arrive at the end </span>cost<span> of </span>$30.78<span>. </span>wholesale price<span>would be 15.20.</span>
Answer:
3
Step-by-step explanation:
replace all x variables with 1 and solve that equation ; f(x)=x-8 so.... f(x) = 1-8
there for f(1)=-7
now, add -7 and 10 for your answer:
f(1)+10= 3
9514 1404 393
Answer:
A. 53.5cm^2
Step-by-step explanation:
The area of the circle is ...
A = πr²
A = 3.14(5 cm)² = 78.5 cm²
The area of the triangle is ...
A = 1/2bh
A = 1/2(10 cm)(5 cm) = 25 cm²
The shaded area is the difference between the circle area and the triangle area:
shaded = 78.5 cm² -25 cm² = 53.5 cm²
_____
<em>Additional comment</em>
As with many multiple-choice questions, you can simply pick the answer that is not outlandish. The circle will fit into a square that is 10 cm on a side, so its total area is less than 100 cm² (eliminates choice B).
The shaded area is definitely more than 1/4 of that 100 cm² square, so choices C and D are eliminated, too. The only choice that is not unreasonable is choice A.
Answer:
The numbers are 18 and 91
Step-by-step explanation:
You can translate the information to two equations:
<em>a value 5 times a smaller number is 1 less than a larger number</em>
5a = b - 1
<em>their difference is 73</em>
b - a = 73
Then you should merge one equation into the other, thereby eliminating one variable. You can do this any way you want. I choose to rewrite the first equation as:
b = 5a + 1
Now I can write 5a+1 in the second equation at the place where b was:
5a + 1 - a = 73
It is now an equation with only one variable, solve by simplifying
4a = 72
a = 18
Now b can be found using b = 5a + 1
b = 91
