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anzhelika [568]
2 years ago
15

what happens to the value of the expression 5/x + 5 as x decreases froma large positive number to a small positive number

Mathematics
1 answer:
agasfer [191]2 years ago
7 0

Answer:

The value increases

Step-by-step explanation:

the smaller the divisor, the larger the quotient.

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Y=x+3 <br> 2x+y=-6<br> Find the solution :
Charra [1.4K]

Answer:

Your solution is (-3,0)

Step-by-step explanation:

Hi,

We know what Y is, so we can plug it into the second equation.

2x + y = -6

2x + (x + 3) = -6

Now, add the like terms...

3x + 3 = -6

3x = -9

x = -3

Now, plug x back in to find y.

y = x + 3

y = (-3) + 3

y = 0

Your solution is (-3,0)

Hope this helps :)

3 0
3 years ago
Select the exclusion that fits best with this problem.<br><br><br><br> 13x^6/51x^4
Damm [24]

ANSWER

x \ne0

EXPLANATION

The given problem is

\frac{13 {x}^{6} }{ 51 {x}^{4}  }

This is defined if and only if

x \ne0

Even the given expression can be simplified to obtain:

\frac{13 {x}^{2} }{ 51}

The exclusion is

x \ne0

5 0
3 years ago
What is the length of the hypotenuse of the triangle when x=7?
Anika [276]

Answer:

c=57.8

Step-by-step explanation:

6*7+4=46

5*7=35

c= 46^2+35^2=57.80138

7 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Graph the points (0,-2), (4,0) and (2,0). If you want to create a parallelogram, which of the following points should used for t
MariettaO [177]

( 2 , - 2 )

................

................

................

8 0
2 years ago
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