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statuscvo [17]
3 years ago
14

Now 11. why is math so hard

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0
A. h = 30Ft * 1.26cm/Ft = 37.8 cm. = Ht. of the model.

37.8cm * 1toothpick/6.3cm = 6 Toothpicks

B. 37.8cm/7.6 = 4.97 hope this helped.
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a line segment with points p(1 2) and q(4 3) is reflected across the line y=x. What are the new coordinates of the points of the
katen-ka-za [31]

Answer:

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

Step-by-step explanation:

we know that

When you reflect a point across the line y= x, the x-coordinate and y-coordinate change places.

so

The rule of the reflection of a point across the line y=x is

(x,y) -----> (y,x)

we have

Points p(1,2) and q(4,3)

Applying the rule of the reflection across the line y=x

p(1,2) ------> p'(2,1)

q(4,3) -----> q'(3,4)

therefore

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

3 0
3 years ago
Need help with this math problem :P <br><br> Thanks In advance
lawyer [7]
F(x) is y
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4 0
3 years ago
Naomi has 50 red beads and white beads. The number of red beads is 1 more than 6 times the number of white beads. How Many red b
Tanya [424]
This is confusing for me
5 0
3 years ago
Why won’t anyone answer my questions argh! how do you draw starlight line graphs
Oduvanchick [21]
The table tells us that the x coordinate. It also tells us that y is always x + 1.

For #1 you plot the coordinate (0, 1).
0 (the x coordinate) is given to us already.
1 (the y coordinate) is needed to be found by the equation.
You would then need to fill in the equation given with the x coorident. 
y = 0 + 1 
Then, solve for y.
0 + 1 = 1
The y coordinate is 1
Go to the horizontal line (x) and find 0.
Then go to the veridical line (y) and find 1.
Then match up the the x and y to plot the coordinate.

You would continue with this equation with the rest of the xs. 

This is a hard concept to explain in just words, so feel free to comment with any more questions. :D

4 0
3 years ago
❊ Simplify :
Nataliya [291]
<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

5 0
3 years ago
Read 2 more answers
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