Answer:
Answer is in picture
Step-by-step explanation:
Hope it is helpful.......
Answer:
Step-by-step explanation:
∫tan(x)dx∫cot(x)dx∫sec(x)dx∫csc(x)dx====−ln∣∣cos(x)∣∣+C=ln∣∣sec(x)∣∣+Cln∣∣sin(x)∣∣+C=−ln∣∣csc(x)∣∣+Cln∣∣sec(x)+tan(x)∣∣+C−ln∣∣csc(x)+cot(x)∣∣+C
Answer:
True
Step-by-step explanation:
Each x input has 1 y output
You forgot to include the given line.
We need the given line to find the slope. The slope of parallel lines are equal. So, the slope of the line of the equation you are looking for is the same slope of the given line.
I can explain you the procedure to help you to find the desired equation:
1) Slope
Remember that the slope-intercept equation form is y = mx + b where m is the slope and b is thye y-intercept.
If you clear y in every equation you get:
a) y = (3/4)x + 17/4 => slope = 3/4
b) y = (3/4)x + 20/4 = (3/4)x + 5 => slope = 3/4
c) y = -(4/3)x - 2/3 => slope = -4/3
d) y = (-4/3)x - 6/3 = (-4/3)x - 2 => slope = -4/3
So, you just have to compare the slope of the given line with the above slopes to see which equations are candidates.
2) Point (-3,2)
You must verify which equations pass through the point (-3,2).
a) 3x - 4y = - 17
3(-3) - 4(2) = -17
- 9 - 8 = - 17
- 17 = - 17 => it is candidate
b) 3x - 4y = - 20
- 17 ≠ - 20 => it is not candidate
c) 4x + 3y = - 2
4(-3) + 3(2) = - 2
-12 + 6 = - 2
-6 ≠ -2 => it is not candidate
d) 4x + 3y = - 6
-6 = - 6 => it is candidate
3) So, the point (-3,2) permits to select two candidates
3x - 4y = - 17, and 4x + 3y = -6.
4) Yet you have to find the slope of the given equation, if it is 3/4 the solutions is the equation 3x - 4y = -17; if it is -4/3 the solution is the equation 4x + 3y = -6.
