Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. D(0,1,1), E(-2,4,3), C(1,2,-1)
Sholpan [36]
Answer:
The three angles of the triangle given above are 23, 73 and 84 correct to the nearest degree. The concept of dot product under vectors was applied in solving this problem. The three positions forming the triangle were taken as positions vectors. The Dot product also known as scalar product is a very good way of finding the angle between two vectors. ( in this case the sides of the triangle given above). Below is a picture of the step by step procedure of the solution.
Step-by-step explanation:
The first thing to do is to treat the given positions in space as position vectors which gives us room to perform vector manipulations on them. Next we calculate the magnitude of the position vector which is the square root of the sun of the square of the positions of the vectors along the three respective axes). Then we calculate the dot product. After this is calculated the angle can then be found easily using formula for the dot product.
Thank you for reading this and I hope it is helpful to you.
Answer:
well bart has 20.00
andy took 19.65
Step-by-step explanation:
subtract 
your answer should be 0.35
Answer:
Step-by-step explanation:
a right triangle is half of a rectangle and the area of a rectangle is
area of rectangle = length × width
Area of a triangle is one half times the length times the width
area of triangle = 1/2 × length × width
in this case
length is the number of the y units
width is the number of x axis unit
area of triangle = 1/2 × length × width
area of triangle = 1/2 × (y units) × (x units) you need to count and insert
the number of units into the
equation
area of triangle = 1/2 × (??? y units ) × (??? x units ) do the math yourself
and see if you get one of
answers