Answer:
You stopped at 2y-4=12
If we add same number to both sides the equation will remain true. For example if we have 5=5, and we add 7 to both sides, we get 12=12 which is also true. Now let's do this with our equation. Add 4 to both sides(to have only y on the left side). We get 2y=16, hence y=8.
Answer. 2y=16
An excluded value is one where the bottom of the fraction = 0.
In your case 1-3x=0
1=3x
x=1/3
At this point, the function does not exist. If you were to draw a graph of it, there wouldn't be a y-value corresponding to x=1/3.
Answer:
This answer is close. Im not 100% sure it is the exact answer but i'm pretty sure it is correct
ANSWER:2412.74029242
Step-by-step explanation:
hope this helped let me know how it goes :)
Answer:
81/16
Step-by-step explanation:
(⅔)-⁴
81/16
= 5.0625
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
