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mafiozo [28]
2 years ago
11

You have the cards numbered 1-10 in front of you.Each time you select a card,it is returned.What is the probability of selecting

a 3 and then an even number

Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

Answer:

Both \:  the \:  moon  \: and  \: earth  \: are  \: in \:  \\  the  \: shape \:  of  \: spheres. \\ Surface\: area  \: of \:  a \: sphere  \: of  \: radius \:  'r' \\

Let d1 be the diameter of the moon and d2 and be the diameter of the earth.Let r1 be the radius of the moon and r2 be the radius of the earth.

given \: d1 =  \frac{1}{4}d2 \\ = > 2r1 =  \frac{1}{4} ×2r2  \\  =>r1 =  \frac{1}{4}×r2 \\ Now,  \: ratio \:  of \:  \:  their  \: surface \:  areas \:  is:  \\ =  s1: s2 \\  = r {1}^{2}: r {2}^{2} \\ = {1}^{2 } : {4}^{2 } \\ =1:16

hope it helps you

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You are out bottle caps, and decide to use Popsicle sticks instead. You measure them, and they are 15.2 cm tall. How many Popsic
satela [25.4K]
It depends on how many Popsicle sticks you are going to use.So, for example, say that you are using 5 Popsicle sticks for the model. What you do is 15.2 x 5, 15.2 being the height of the sticks and 5 for the number of sticks you are using. The answer will be 76 cm tall.           21                                                                                                                     15.2                                                                                                               x    5                                                                                                                ---------                                                                                                             76.0
3 0
3 years ago
Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
zloy xaker [14]

Answer:

Step-by-step explanation:

Hello!

Use these data to calculate the chi-square statistic. Report your calculated chi-square statistic to two decimal places.

In this example, the study variable is X: genotype of a single locus two allele gene that codes the mating call of tree frogs. Categorized: S₁S₁, S₁S₂, and S₂S₂.

Usually, when you have a sample of observed genotypes of a gene of interest, the goal is to check if these genotypes follow a theoretical model such as the frequency models proposed by Mendel.

In Mendelian genetics, when two heterozygous individuals (Aa, Aa) from the F1 generation are crossed, you expect the next generation (F2) to show the genotypic ratio 1:2:1 ⇒ This model means that out of 4 descendants 1 will have the genotype AA, 2 will have the genotype Aa and 1 will have the genotype aa. Since there is no theoretical model specified I'll use the mendelian ratio 1:2:1.

If this theory applies to the population then we'll expect that the proportion of the first genotype is P(S₁S₁)= 0.25, the second P(S₁S₂)= 0.5 and the third P(S₂S₂)=0.25

To test if the observed genotypes follow the theoretical model you have to apply a Chi-Square Goodness of Fit Test.

For this test the hypotheses are:

H₀:P(S₁S₁)= 0.25; P(S₁S₂)= 0.5; P(S₂S₂)=0.25

H₁: The data is not consistent with the specified distribution.

α: 0.05

Statistic: X^2= sum(\frac{(o_i-e_i)^2}{e_i} )~X^2_{k-1}

Where:

oi: Observed frequency for the i- category

ei: Expected frequency for the i-category

k= number of categories

The rejection region for this test is one-tailed to the right. This is so because if the observed and expected values are too different (the chi-square value will be high) this will mean that the population doesn't follow the theoretical model and thus reject the null hypothesis. If the differences between what's observed and what's expected are small, this will mean that the population follows the theoretical model (and you'll obtain a small chi-square value) and you will not reject the null hypothesis.

The critical value is:

X^2_{k-1; 1 - \alpha }= X^2_{3;0.95}= 7.815

If the statistic is at least 7.815, the decision is to reject the null hypothesis.

If the statistic is less than 7.815, the decision is to not reject the null hypothesis.

Step 1 is to obtain the expected frequencies for each category:

e_i= n*P_i

e_{S_1S_1}= n * P(S_1S_1)= 1341*0.25= 335.25

e_{S_1S_2}= n * P(S_1S_2)= 1341 * 0.5= 670.5

e_{S_2S_2}= n * P(S_2S_2)= 1341*0.25= 335.25

Note: the summatory of the expected frequencies is equal to the total of observations ∑ei= n. If you have doubts about your calculations, you can add them to check it: ∑ei= 335.25 + 670.5 + 335.25= 1341

X^2= (\frac{(987-335.25)^2}{335.25} )+(\frac{(333-670.5)^2}{670.5} )+(\frac{(21-335.25)^2}{335.25} ) = 1731.50

Decision: Reject null hypothesis.

I hope this helps!

3 0
3 years ago
PLZZZZ HELP IM FAILING THIS CLASS I NEED THISSS!?
lina2011 [118]

Answer:

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4 0
3 years ago
Simplifying rational expressions<br><br> h-2 divided by h squared+3h-10
EleoNora [17]
Long division here. Divide h^2+3h-10 by h-2 to get h+5. That means when you multiply h-2 by h+5, you get what you started with, h^2+3h-10
4 0
3 years ago
Please help me asap PLEASEEEEEEEE I CANT DO THIS
Sergeeva-Olga [200]

Answer:

1. Yes

2. Exactly Double

Hope this helps and have a great day :)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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