The answer is
96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the
z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the
percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is
96%.
Using the probability concept, it is found that there is a 0.7361 = 73.61% probability that the senior selected will not be from high school b given that the senior responded with a choice other than college.
<h3>What is a probability?
</h3>
- A <em>probability </em>is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
Researching the problem on the internet, it is found that:
- 538 seniors responded with a choice other than college.
- Of those students, 99 + 83 + 49 + 31 + 63 + 71 = 396 are not from high school b.
Hence:

0.7361 = 73.61% probability that the senior selected will not be from high school b given that the senior responded with a choice other than college.
You can learn more about the probability concept at brainly.com/question/26148436
Answer: (8a^3x^3)/81
Step-by-step explanation: Simplifying the expression :)
Answer:
no -9/4 is irrational
Step-by-step explanation:
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