Answer:
the answer is letter a
Step-by-step explanation:
ok there
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
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Based on the given variation, y does not vary directly with x and the constant of variation are 8, 3.2 and 1.25 respectively.
<h3>Variation</h3>
y = k × x
where,
k = constant of proportionality
y = -40
x = -5
y = k × x
-40 = k × -5
-40 = -5k
k = -40/-5
k = 8
when,
y = 8 and x = 2.5
y = k × x
8 = k × 2.5
8 = 2.5k
k = 8/2.5
k = 3.2
when,
y = 5 and x = 4
y = k × x
5 = k × 4
5 = 4k
k = 5/4
k = 1.25
Learn more about variation:
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Answer:
use identity (a - b) ^3 = a^3 - b^3 - 3ab (a - b)
here, a = x ^2
b = -1
= (x^2)^3 - (-1)^3 - 3 * x ^2 * -1 ( x^2 - (-1) )
x^6+ 3 x^2 ( x ^2 + 1)
I think this is the answer
Answer:
-3x+6
Step-by-step explanation: