A homeowner has 60 feet of fencing material to enclose a rectangular area for his pets to play in. One side of the house will be
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From what I imagine in the problem description, the toy is located on the ground. Then, Belkis is pulling on the string to keep the toy moving just like how you put a leash on a dog. My illustration is shown in the picture. The F arrow is where Belkis pulls it. Its component vectors are Fx and Fy, as shown.
From the figure, we can see that it forms a right triangle. So, it makes it easy because the pythagorean theorems are applicable and we can easily use trigonometric functions. First, let's determine Fy which is located opposite to the angle. Since we know the hypotenuse F to be 1.5 N, so we use the sine function:
sin 52° = Fy/F = Fy/1.5
Fy = 1.182 N
For the horizontal component, Fx is parallel to the adjacent side with respect to the angle. Thus, we use the cosine function.
cos 52° = Fx/F = Fx/1.5
Fx = 0.923 N
From the figure, we can see that it forms a right triangle. So, it makes it easy because the pythagorean theorems are applicable and we can easily use trigonometric functions. First, let's determine Fy which is located opposite to the angle. Since we know the hypotenuse F to be 1.5 N, so we use the sine function:
sin 52° = Fy/F = Fy/1.5
Fy = 1.182 N
For the horizontal component, Fx is parallel to the adjacent side with respect to the angle. Thus, we use the cosine function.
cos 52° = Fx/F = Fx/1.5
Fx = 0.923 N