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soldier1979 [14.2K]
3 years ago
8

The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli

d and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line. y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3

Mathematics
2 answers:
Rudiy273 years ago
6 0
Solid...(-3,0)(-4,-1)...shaded below the line

slope = (-1-0) / (-4-(-3) = -1/(-4 + 3) = -1/-1 = 1

y = mx + b
-1 = 1(-4) + b
-1 = -4 + b
-1 + 4 = b
3 = b

this line is : y < = x + 3 <== (thats less then or equal)
====================
solid...(1,1)(2,-1)...shaded below the line

slope = (-1-1) / (2-1) = -2/1 = -2

y = mx + b
1 = -2(1) + b
1 = -2 + b
1 + 2 = b
3 = b

this line is : y < = -2x + 3 <== (thats less then or equal)

Murrr4er [49]3 years ago
6 0

Answer:

The answer is d on ed2020

Step-by-step explanation:

i know because im doing the lesson

the next page has:

Which equation represents an inequality in the system of inequalities shown in the graph? y<2x+2

Which point is a solution to the system? -1,-2

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Standard Form           Equivalent Form            Extreme Values

y=x^2-6x+17                   (x-3)^2+8                        (3,8)

y=x^2+8x+21                  (x+4)^2+5                        (-4,5)

y=x^2-16x+60                 (x-8)^2-4                         (8,-4)

Step-by-step explanation:

1) Standard form:

y=x^2-6x+17

Equivalent Form:

Can be found using completing the square method.

y=x^2-6x+17\\y=x^2-2(x)(3)+(3)^2-(3)^2+17\\y=(x-3)^2-9+17\\y=(x-3)^2+8

So, Equivalent form is: (x-3)^2+8

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate is: 2x-6

Now, put the derivate equal to zero: 2x-6 = 0

2x=6\\x=6/3 \\x=3

Maximum value can be found by putting minimum value in the given function:

Put x = 3 and solve:

(3)^2-6(3)+17\\9-18+17\\9-1\\=8\\

So, the extreme values is: (3,8)

2) Standard form:

y=x^2+8x+21

Equivalent Form:

Can be found using completing the square method.

y=x^2+8x+21\\y=x^2+2(x)(4)+(4)^2-(4)^2+21\\y=(x+4)^2-16+21\\y=(x+4)^2+5

So, Equivalent form is: (x+4)^2+5

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2+8x+21 is: 2x+8

Now, put the derivate equal to zero:

2x+8 = 0\\2x=-8\\x=-8/2 \\x=-4

So, minimum value is: -4

Maximum value can be found by putting minimum value in the given function:

Put x = -4 and solve:

x^2+8x+21\\=(-4)^2+8(-4)+21\\=16-32+21\\=5

So, Maximum value is: 5

So, the extreme values is: (-4,5)

3) Standard form:

y=x^2-16x+60

Equivalent Form:

Can be found using completing the square method.

y=x^2-16x+60\\y=x^2-2(x)(8)+(8)^2-(8)^2+60\\y=(x-8)^2-64+60\\y=(x-8)^2-4

So, Equivalent form is: (x-8)^2-4

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2-16x+60 is: 2x-16

Now, put the derivate equal to zero:

2x-16 = 0\\2x=16\\x=16/2 \\x=8

So, minimum value is: 8

Maximum value can be found by putting minimum value in the given function:

Put x = 8 and solve:

x^2-16x+60\\=(8)^2-16(8)+60\\=64-128+60\\=-4

So, Maximum value is: -4

So, the extreme values is: (8,-4)

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