Answer:
When ocean salt water evaporates, the salt in the water is left in the water. This causes the salt water to become heavily filled with salt.
Explanation:
The question offers an image containing information regarding the patient by the name of Anita and her actions prior to arriving at the hospital.
We can describe the patient and her timeline up to her hospital visit by mentioning information about her:
- <em>Name </em>
- <em>Occupation</em>
- <em>Weight</em>
- <em>Age</em>
- <em>Actions prior to her hospital visit</em>
The patient in question is a 108 pound, 36-year-old female by the name of Anita Martin. The patient is indicated to be a security guard. As per the information given, the patient seems to have been working a night shift in a building in the vicinity of a recent train wreck that seems to have released chlorine gas. On her way to her car, Anita was exposed to chlorine gas, due to which she decided to drive to the hospital.
With this information, we will have properly described the patient in question so that the medical professionals at the hospital will have all the information necessary to proceed with an effective treatment plan for Anita's condition.
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Answer:
she should look for a tall dominant gene in a man or TT while she would be a tt.
Explanation:
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>