9514 1404 393
Answer:
none
Step-by-step explanation:
No work is required to maintain an object at a constant speed with no change in direction. Work is only done when an object is accelerated, or moved some distance in the direction of the net force applied.
you would do no work
The answer would be 234. You will multiply 28 by 9 and minus 18.
Answer: 4(x-x2)
Step-by-step explanation: please mark brailyest
Answer:
D. 1
Step-by-step explanation:
We have the expression, 
We get, eliminating the cosecant function,

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,
i.e. 
i.e. 
Since, we know that, 
Thus,

So, after simplifying, we get that the result is 1.
Hence, option D is correct.